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Re: What's reason cause the insert delay in tempdb and how to improve it?

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thanks, Mark. Here is the results with your guide:

 

sp_helpdb tempdb

go               

    name db_size owner dbid created status 

1 tempdb                      2003.0 MB sa                       2 Oct 14, 2014       select into/bulkcopy/pllsort, trunc log on chkpt, ddl in tran, abort tran on log full 

                

    name attribute_class attribute int_value char_value comments 

1 tempdb buffer manager cache binding 1 tempdb data cache [NULL] 

                

    device_fragments size usage created free kbytes   

1 master       3.0 MB data only           Apr  9 2011 11:25AM            1866   

2 tempdb_data    1500.0 MB data only           Apr  9 2011  1:27PM         1529940   

3 tempdb_logs     500.0 MB log only             Apr  9 2011  1:27PM not applicable   

                

              

1 log only free kbytes = 509930                                   

 

 

 

 

sp_helpdevice

    device_name physical_name description status cntrltype device_number low high 

go        

19 tempdb_data /db/oe/tempdb/tempdb_data.dat                 special, dsync off, physical disk, 1500.00 MB 2 0 3 50331648 51099647 

20 tempdb_logs /db/oe/tempdb/tempdb_logs.dat                 special, dsync off, physical disk, 500.00 MB 2 0 4 67108864 67364863         

 

 

 

 

---Without insert

exec sp_1 -- does the basic select * from mytab

      

    

        

      

1 Total actual I/O cost for this command: 0.   

2 Total writes for this command: 0   

3   

4 Execution Time 0.   

5 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms.   

        

      

1 10/15/2014 1:00:49.613 PM   

        

      

1 Total actual I/O cost for this command: 0.   

2 Total writes for this command: 0   

3   

4 Execution Time 0.   

5 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms.   

6 Total actual I/O cost for this command: 0.   

7 Total writes for this command: 0   

8   

9 Execution Time 0.   

10 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 3 ms.   

        

    status 

1 11150 C. 

2 7795 D. 

3 13618 DIR 

4 1445 EXE 

5 48 GMD 

6 55 IMD 

7 66471 M. 

8 374 NMD 

9 2383 REG 

        

      

1 Table: tab1 scan count 4, logical reads: (regular=124929 apf=0 total=124929), physical reads: (regular=0 apf=0 total=0), apf IOs used=0   

2 Table: tab2 scan count 204728, logical reads: (regular=235956 apf=0 total=235956), physical reads: (regular=0 apf=0 total=0), apf IOs used=0   

3 Table: tab2 scan count 1, logical reads: (regular=5 apf=0 total=5), physical reads: (regular=0 apf=0 total=0), apf IOs used=0   

4 Table: Worktable1  scan count 5, logical reads: (regular=151 apf=0 total=151), physical reads: (regular=0 apf=0 total=0), apf IOs used=0   

5 Total actual I/O cost for this command: 722082.   

6 Total writes for this command: 0   

7   

8 Execution Time 0.   

9 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 1796 ms.   

        

      

1 10/15/2014 1:00:51.413 PM   

        

      

1 Total actual I/O cost for this command: 0.   

2 Total writes for this command: 0   

3   

4 Execution Time 0.   

5 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms.   

        

 

 

 

 

---With insert

exec sp_2 -- does the basic select * from mytab

 

 

      

    

1 Total actual I/O cost for this command: 0. 

2 Total writes for this command: 0 

4 Execution Time 0. 

5 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms. 

      

    

1 10/15/2014 1:01:35.833 PM 

      

    

1 Total actual I/O cost for this command: 0. 

2 Total writes for this command: 0 

4 Execution Time 0. 

5 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms. 

6 Total actual I/O cost for this command: 0. 

7 Total writes for this command: 0 

9 Execution Time 0. 

10 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms. 

11 Table: #table1______02000450014068719 scan count 0, logical reads: (regular=18 apf=0 total=18), physical reads: (regular=0 apf=0 total=0), apf IOs used=0 

12 Table: tab1 scan count 1, logical reads: (regular=121953 apf=0 total=121953), physical reads: (regular=0 apf=0 total=0), apf IOs used=0 

13 Table: tab2 scan count 204728, logical reads: (regular=229304 apf=0 total=229304), physical reads: (regular=0 apf=0 total=0), apf IOs used=0 

14 Table: tab2 scan count 1, logical reads: (regular=5 apf=0 total=5), physical reads: (regular=0 apf=0 total=0), apf IOs used=0 

15 Table: Worktable1  scan count 1, logical reads: (regular=29 apf=0 total=29), physical reads: (regular=0 apf=0 total=0), apf IOs used=0 

16 Total actual I/O cost for this command: 702618. 

17 Total writes for this command: 0 

18 

19 Execution Time 31. 

20 SQL Server cpu time: 3100 ms.  SQL Server elapsed time: 3226 ms. 

      

    

1 10/15/2014 1:01:39.060 PM 

      

    

1 Total actual I/O cost for this command: 0. 

2 Total writes for this command: 0 

4 Execution Time 0. 

5 SQL Server cpu time: 0 ms.  SQL Server elapsed time: 0 ms. 

 

The difference is:

11 Table: #table1______02000450014068719 scan count 0, logical reads: (regular=18 apf=0 total=18), physical reads: (regular=0 apf=0 total=0), apf IOs used=0

 

Does this cause performance difference?


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